Tuesday, November 27, 2018

Timer in Excel Using VBA

Gift Your self a Nice Timer in Excel Using VBA

Just Give It A Try!


Step 1: Insert an Userform

Step 2: Locate the SHOWMODAL Property of The Userform and make it FALSE

Step 3: Design the userform you as you are seeing in video or you can design your own. it's up to you.

Step 4: Inert a New Module and paste the following code into it.

Sub ()
UserForm2.Show vbModeless
End Sub

Step 5: Double Click on a button on the userform which will start the clock and paste the following code in it.

Private Sub CommandButton1_Click()
Do
DoEvents
UserForm2.Label1.Caption = VBA.Time
Loop
End Sub

Step 6: Paste the following code to close the Timer
Private Sub CommandButton2_Click()
Unload UserForm2
End Sub

Step 7: Put a Button on the Sheet and assign macro named as "Open_Timer"
and it's done! enjoy friend.

By Kamal Bharakhda

Sunday, November 25, 2018

The completely dynamic way to Rename the Shapes in Excel VBA




Sub Rename_Shape()

Dim SheetName As String
SheetName = "Sheet1"

Dim WS As Worksheet
Set WS = ThisWorkbook.Sheets(SheetName)

WS.Activate

Dim Shp As Shape

Dim ShapeName As String
ShapeName = vbNullString

Dim ShapeSelected As String
Dim NewNameofShape As String

For Each Shp In WS.Shapes
ShapeName = ShapeName & " ' " & Shp.Name & " ' "
Next Shp

ShapeSelected = VBA.InputBox(ShapeName & " Please Input the Shape names in Inverted Comma", "Select Shape")

NewNameofShape = VBA.InputBox("Please enter new name of Shape you have selected", "Rename Shape")

If ShapeSelected = vbNullString Or NewNameofShape = vbNullString Then Exit Sub

WS.Shapes(ShapeSelected).Name = NewNameofShape

End Sub



Points to Remember

1. The First Inpubox will provide you the list of the Shape available in the Inverted Comma. You need to type the name in the input area which you want to rename is

2. A second input box will ask you to enter a new name.

and there you go.

Saturday, November 24, 2018

Fill ComboBox based on Seach Criteria

One the best approch for this requirement is to add one textbox as search bar which provides the same result you reuired.

Here we need to focus on three things. I'm cosidering that your combobox is in the userform1
and your students data list is in the sheet1.

Now,

There are two events you need configure to perform this task.

1. UserForm_Initialize
2. TextBox1_Change

and the one sub procedure which will populate the result based on the keyword in the textbox

3. Populate_Combobox

Now

Coding for the 1 & 2 is the same

Private Sub TextBox1_Change()
Populate_Combobox
End Sub

Private Sub UserForm_Initialize()
Populate_Combobox
End Sub

Now let's see the code for the Sub Procedure

Private Sub Populate_Combobox()
Dim I As Long
I = 2
Dim LenofStr As Long
LenofStr = 0
With UserForm1
.ComboBox1.Clear
If .TextBox1.Value = vbNullString Then
Do Until Sheet1.Cells(I, 1).Value = Empty
.ComboBox1.AddItem Sheet1.Cells(I, 1).Value
I = I + 1
Loop
Else
LenofStr = VBA.Len(.TextBox1.Value)
Do Until Sheet1.Cells(I, 1).Value = Empty
If VBA.Left(VBA.UCase(Sheet1.Cells(I, 1).Value), LenofStr) = VBA.UCase(.TextBox1.Value) Then
.ComboBox1.AddItem Sheet1.Cells(I, 1).Value
End If
I = I + 1
Loop
End If
End With
End Sub

I have also attached images with this post




BOLD a Part of the Cell Value

Q:  D1=(A1&B1)...I want the result of B1 Bold when result show i.e. Biplab (A1) & Rs.12/-(B2). In Cell No. C1 there is formula =(A1&" "B1)...Now Result I want "Biplab Rs.12/-"..... Only Rs.12/- is BOLD. (Note: Length of B1 is not fixed)

Let's create a function called Bold which will make any character under the function to bold. and you can use it directly in the sheet using formula feature. 



here is the two thing.

Put the Following function in the Module

Function BOLD(ByRef Text As String) As String

Text = "!" & Text
BOLD = Text

End Function

Now Goto the Sheet and choose we will work on Worksheet_Change Event 

here is the Code. 

Private Sub Worksheet_Change(ByVal Target As Range)

Dim I As Variant
I = Target.Value

Dim A As String
Dim B As String

Dim ALEN As Integer
Dim BLEN As Integer

Dim TargetColumnNo As Integer
TargetColumnNo = 3

If Target.Column = TargetColumnNo Then

If VBA.InStr(1, I, "!") > 0 Then
A = VBA.Left(I, Application.WorksheetFunction.Find("!", I, 1) - 1)
B = VBA.Mid(I, VBA.InStr(1, I, "!") + 1, VBA.Len(I) - VBA.InStr(1, I, "!"))
ALEN = VBA.Len(A)
BLEN = VBA.Len(B)
Target.Value = A & " " & B
Target.Characters(ALEN + 2, BLEN).Font.FontStyle = "Bold"
Else
Exit Sub
End If

End If

End Sub

Now Suppose in the Sheet1 and Column 3 would be your target column then 

write the following formula and you will get the required result. 

=A1&BOLD(B1)

Thank you. 

Saturday, November 17, 2018

Replace Excel's Data Validation Drop-down with Smart Userfrom Based Mini Tool


Creating Dropdown from the Validation part of the excel is very easy and very fundamental thing we should know as an Excel Enthusiastic.

When our project required the same list of things to be chosen from the single cell usually make things done with creating the drop-down list from the Data Validation Tool which is inbuilt in Excel.

Now, Sometimes you might have faced or not, but each cell of the column requires the same list of things for selection. I was usually ending up by drag down the dropdown list to the nth row which could be messy sometimes. and it even no looks cool. and you even can't put things apart from the list.

What I have done here is, You don't require a dropdown list at all. Just see the video and you will get what I have done.

The advantage of this tool is you don't need to create hundreds of dropdown in the same column when everything is available to you in just a double-click.

To compile this tool I have required following two scopes.

1. Worksheet Code
2. Userform Design and Codes

You can design the userform and it looks easy not a big deal.

Now let's move towards coding of Worksheet
======
Private Sub Worksheet_BeforeDoubleClick(ByVal Target As Range, Cancel As Boolean)
   
    If Target.Column = 2 Then
        LISTBOX.Show
    End If
    
End Sub
======
I have used BeforeDoubleClick Event to initiate the things.

Now, as we double click on the cell on column two, the Sheet Code will sense it and trigger the event and will force userform to appear.

More to the Second part of the coding

=====
Private Sub UserForm_Initialize()

    Application.ScreenUpdating = False
    
    Dim DB As Worksheet
    Set DB = Sheets("DATABASE")
        
    Dim I As Long
    I = 1
    
    LISTBOX.ListBox1.Clear
    
    Do Until DB.Cells(I, 2).Value = Empty
        LISTBOX.ListBox1.AddItem DB.Cells(I, 2).Value
    I = I + 1
    Loop

    Application.ScreenUpdating = True

End Sub
=====

(Above code will take each item of the list from the Place called Database Sheet where you have listed all the details over there with Heading.)

Now DOuble Click even to input userform data into the sheet which the same part of userform coding

======
Private Sub ListBox1_DblClick(ByVal Cancel As MSForms.ReturnBoolean)
    
    With LISTBOX.ListBox1
        If .ListIndex = -1 Then Exit Sub
        ActiveCell.Value = .List(.ListIndex)
        Cells(ActiveCell.Row, ActiveCell.Column + 1).Activate
        Unload LISTBOX
    End With
    
End Sub
======

Now Coding for the Add New Button. this coding will add Item to the list.

Private Sub CommandButton1_Click()
    
    Dim I As Variant
    Dim J As Variant
    
    If ActiveCell.Column = 2 Then
        I = VBA.InputBox("Please Enter New Tail No.:", "Add New Tail No. in The Database")
        If I = vbNullString Then
            Exit Sub
        Else
            J = NewRow("DATABASE", 2)
            Sheets("DATABASE").Cells(J, 2).Value = I
            Dim DB As Worksheet
    Set DB = Sheets("DATABASE")
     
    I = 1
    
    LISTBOX.ListBox1.Clear
    
    Do Until DB.Cells(I, 2).Value = Empty
        LISTBOX.ListBox1.AddItem DB.Cells(I, 2).Value
    I = I + 1
    Loop
        End If
  end if 

end sub
======

So This is it. Please Try. and create more ways to use it in a more effective way.

Thank you

- Kamal Bharakhda

https://www.youtube.com/watch?v=hAEL7TeqOnQ

Friday, November 2, 2018

What is the formula for calculating the inclusive tax amount from a given amount?

Let's answer it with mathematical approach. You might required to use it in the formula or in VBA. This simplification will help you for sure.

Assume few variables

X = Product's Original Amount without Tax

Y = Inclusive Tax Amount (i.e. you're looking)

Z = Product's Amount with Tax or MRP or Included tax amount.

Q = Tax %

-

So basic foundation of product's final amount after tax including is like,

X + Y = Z

Now, Y = ( Q * X ) / 100

So the equation become,

X + ( Q * X ) / 100 = Z

Now solve the above equation to find the value of X

X = ( Z * 100 ) / ( Q + 100 )

And to get the value you required put this value of X back to the initial equation

X + Y = Z

{( Z * 100 ) / ( Q + 100 )} + Y = Z

Now solve for Y,

Y = ( Z * Q ) / ( Q + 100 )

So put known values of Z & Q in the above equation and you will get the required value.

Good day.

Kamal Bharakhda

Friday, October 5, 2018

4 digit PIN Style Login System

Hello Beautiful People,

Here I'm giving away the most unique way to login in excel based applications as 4 digit PIN style.

It's Fast and secured. And even with this post, you will receive the VBA Code to change the PIN No. by the authorized user.

So, What happened yesterday, my traditional login system, which has a username and password, as usual, has become more boring. I have just completed a development of an application for billing purpose and I was testing it and I felt, I should have something more fast and furious and secured way of login system. I was thinking of for the idea and suddenly my mom came to my room and asked me for my VISA debit card and she also asked me the PIN no. of the same card. But that leaves the fantastic idea on me.

I have quickly developed something very simple and sober which works exactly like what I have assumed. The user just needs to type 4 digit pin and without any control and by using of Textbox Change Event Mechanism, I get the best result out it. and it worked like a HERO!.

Now, I'm giving away the VBA code for the Userform and Module for Changing PIN No. on any time by the Authorized User.

Here are the things you need to prepare before placing of VBA Codes.

1. User form with only One TextBox and Designed it just like what you can see in the middle of the screenshot attached to this Post.



2. Place a Command Button anywhere you want and caption it as "Change PIN No."

3. Now Open the Userform and Double Click on the Textbox and put this code in it.

Private Sub TextBox1_Change()

Application.ScreenUpdating = False

Dim RealPass As Long
RealPass = THENEWGST.Sheets("REGISTRY").Range("Z1").Value
With LOGIN
If VBA.Len(.TextBox1.Value) = 4 Then
If VBA.Val(.TextBox1.Text) = VBA.Val(RealPass) Then
'Call here the next Procedure you want to execute after entering of successful PIN No. 
Else
MsgBox "Wrong PIN" & vbNewLine & vbNewLine & "Call us at 919328093207 for Any Query", vbExclamation, "Zyest Solutions"
.TextBox1.Value = vbNullString
End If
End If
End With

Application.ScreenUpdating = True

End Sub

4. Then Goto the button where you captioned it as "Change PIN No." and Put the following VBA Code in the Sub.

Private Sub PIN_CHANGING_PROCESS()

Application.ScreenUpdating = False

On Error Resume Next
Dim I As Variant
Dim J As Variant
Dim K As Variant
Dim L As Variant
L = THENEWGST.Sheets("REGISTRY").Range("Z1").Value

I = VBA.InputBox("Please Enter Your Current PIN", "PIN Changing Process")

If VBA.Val(I) = VBA.Val(L) Then
'/-------
J = VBA.InputBox("Please Enter Your NEW PIN", "PIN Changing Process")

If VBA.IsNumeric(J) = False Then
MsgBox "Only Numeric Inputs Are Allowed", vbExclamation, "Validation by Zyest Solutions"
Exit Sub
End If
If VBA.Len(J) <> 4 Then
MsgBox "Only Four [4] Digits are allowed as PIN", vbCritical, "Validation By Zyest Solutions"
Exit Sub
End If
'/-------
K = VBA.InputBox("Please Enter Your NEW PIN Again", "PIN Changing Process")

If VBA.IsNumeric(K) = False Then
MsgBox "Only Numeric Inputs Are Allowed", vbExclamation, "Validation by Zyest Solutions"
Exit Sub
End If
If VBA.Len(K) <> 4 Then
MsgBox "Only Four [4] Digits are allowed as PIN", vbCritical, "Validation By Zyest Solutions"
Exit Sub
End If
'/-------
If VBA.Val(J) = VBA.Val(K) Then
THENEWGST.Sheets("REGISTRY").Range("Z1").Value = VBA.Val(J)
MsgBox "Great! Your PIN No. is Changed!" & vbNewLine & vbNewLine & "Your New PIN No. is : " & J, vbOKOnly, "Zyest Solutions"
Else
MsgBox "PIN No. Doesn't matched, Please do it again", vbCritical, "Validation By Zyest"
End If
'/-------
Else
MsgBox "Wrong PIN No. Please Enter Correct PIN No.", vbExclamation, "Validation By Zyest Solutions"
End If

Exitit:

Application.ScreenUpdating = True

End Sub

Note: "THENEWGST" is my workbook name. So you can replace it with ThisWorkBook

So You can modify this code according to your requirements.

Enjoy it and try it. and leave your comments here. thanks.

Regards
Kamal Bharakhda
kamal.9328093207@gmail.com
+919328093207

IsValidPasswordString Function

'Following function will verify if the password string contains following characters or not? Rem : List of Characters Group - ASCII Rem ...